I believe this is a quick one, but I can’t figure it out, suppose I have a 45 degree curve from 0,0,0. And I want to control its curvature with a conic graph mapper, but keeping the start and end points. Like so:
I think I didn’t explain myself clearly, I need to be able to conserve previous end points of an already existing curve.
Posting a model is the best way to express yourself clearly.
It doesn’t matter if the curve is a straight line or not…
Couldnt you dispatch item no 0 and -1 of the points and later merge them together to make the curve?
Thank you Joseph. I had not model because I reduced my problem to its core elements. I was able to apply the model to any curve in space, but I am afraid I did not take into account that the direction of the curve matters. If you have any ideas I would much appreciate it.
Graph Mapper Curves.gh (47.8 KB)
Please understand. If you had posted this model originally as your goal, giving 3D context to the problem, your goal would have been SO MUCH CLEARER!!!
Graph_Mapper_Curves_2018Mar27a.gh (42.5 KB)
Trouble with a simple geometrical problem
I understand Joseph, I apologize. Simplified the problem a bit too much.
This is the expected result. I did this fast for visual purposes by doing the curves both ways and then culling out the ones that did not coincide with the end points. I believe any other solution to be more efficient and clean.
Graph Mapper Curvesre.gh (46.9 KB)
Hope you had fun. I have no idea what you’re doing and am not about to replicate your code from a screen shot. I know better than to respond to threads where no code is posted with the original question (which was vague and misleading in this case).
I disagree, I already explained the approach to the problem, reducing it to its core elements. (Which in the end worked). No model was needed/relevant because I was looking for a grometrical solution that I didnt had. You can see that when a model was relevant it was uploaded.
But in any case I just uploaded in case you were interested in the solution and result, and for other people that might find it helpful of course.
Its ironic that you actually helped me a lot more without a model and a simplified question than when I uploaded it with a more complex one. Thank you for that.