Select and activate a layout from a list of layouts

Rhino Rhino for Windows
,
1

Hi

How can I make a script where the user selects a layout from layout names and then makes that layout active?
Or in other words - I get an error "expected RhinoView, got str" - So how to find a RhinoView by having a name?

(this script is just a part of bigger one, but I can’t get this part to work…)

import Rhino
import scriptcontext as sc
import System.Drawing
import rhinoscriptsyntax as rs



def make_details():
    layoutNames = []
    page_views = sc.doc.Views.GetPageViews()

    for page_view in page_views:
        layoutNames.append(page_view.PageName)
        
    layout = rs.ComboListBox(layoutNames, "Select layout")
    if layout: 
        sc.doc.Views.ActiveView = layout
        sc.doc.Views.Redraw()
        print layout

if __name__ == "__main__":
    pageview = sc.doc.Views.ActiveView
    if type(pageview) == Rhino.Display.RhinoPageView:
        print "This tool only works in the model space."
    else:
        make_details()
2

I guess Genesis was right when they were singing:

There’s too many men, too many people
Making too many problems
And there’s not enough love to go around

Anyways, I found a solution, maybe not the proper way, but it might help in a case when you want to use rhinoscriptsyntax ComboBox for user interface and retrieve an item based on that selection from another list:

import Rhino
import scriptcontext as sc
import System.Drawing
import rhinoscriptsyntax as rs



def make_details():
    layoutNames = []
    page_views = sc.doc.Views.GetPageViews()

    for page_view in page_views:
        layoutNames.append(page_view.PageName)
        
    layoutName = rs.ComboListBox(layoutNames, "Select layout")
    if layoutName == None:
        return()
        
    if layoutName: 
        for page_no in range(len(layoutNames)):
            if(layoutNames[page_no] == layoutName):
                layout = page_views[page_no]
                if layout: 
                    sc.doc.Views.ActiveView = layout
                    sc.doc.Views.Redraw()

if __name__ == "__main__":
    pageview = sc.doc.Views.ActiveView
    if type(pageview) == Rhino.Display.RhinoPageView:
        print "This tool only works in the model space."
    else:
        make_details()