hi i’m trying to create scissor structure that the radus depend on one another
i got the three radusis depend on one another but i’m trying to fugure out how to make the lines meet in the 1/3( the second circle)
anyhelp? 
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sure,
that what i got till now
15.03.22.gh (5.8 KB)
i’m trying to do something like this that them the 2 lines meet in the 1/3
Looks like you need to change the angle between the lines.
If you want to meet them exactly at 1/3 you can’t vary the angle.
Start by using Divide with 3 segments to find the thirds, then Rotate the line with Copy=Yes to make the second, then the third,the fourth etc.
Hope this helps you.
helps alot thank u
Hi @Maria5,
It is worth considering the geometry of the scissor pairs:
The upper and lower sections can be considered as two similar triangles. As the bars are divided at 1/3 length, the diagonals are in the ratio 2:1. This means the distances between the two outer tips and the two inner tips are in the ratio 2:1 and the ‘heights’ of the triangles are also in the ratio 2:1.
Lines extended through each outer tip and the inner tip of its scissor pair will pass through a common point around which the scissors are arrayed. See for example the line marked diagonal.
If you draw a bisector from that centre point through the middle of a scissor pair then the offset from that line to the outer tip and the offset to the inner tip are again in the ratio 2:1. That means that the diagonal will cross the bisector the same distance below the inner tips as the outer tips are above them.
So, again by similar triangles, the radius of the circle the inner tips are arrayed on is the same as the distance between an outer tip and it’s pair’s inner tip on the diagonal.
Note that, as illustrated by the second example, nothing changes if the angle between the crossing scissor arms is varied, except for the radius of the circle. (That changes because the mid point of the base of the inner triangle is further from the circle, the wider the triangle gets).
HTH
Jeremy
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