This question has been asked but never successfully resolved [i think]
these boxes have been drawn using the make2d command
by simply rotating the camera in isometric view, i can make dimetric or trimetric.
say if i rotate downwards it will give me a dimetric
if i rotate to the side and down or up it will give me trimetric
the third trimetric [on lean] is done by adding -15 degrees rotation in the properties section.
i would like to know if the rhino engine uses the correct [strict] scaling method in scaling the x,y,z axis as the lengths in dimetric and trimetric differ, i assume it would be so?!
I have no problem with measuring the lengths, the make2d command gives me accurate geometrical information, i am going to try and reword what i asked to see if you or anybody else will know the answer:
according to this axonometric calculator:
"tamivox axonomertric calculator’
the angles of 30 inclination left + 30 inclination right gives lengths of 0.816497.
The rhino make2d command of a 100x100x100 box in isometric projection gives me the same result, @81.65…
rotating the camera to the left and then towards the zenith gives the the trimetric [pictured]. The ‘tamivox’ calculator, with angles of 16.39 inclination left + 48.57 inclination right, returns lengths of 0.928761 [left], 0.816536 [centre] and 0.686056 [right].
So therefore the rhino isometric view gives true axonometric at the give rotation of the model
, i am trying to work out how i can use camera rotation, to specify exactly what dimetric or trimetric angle desired, ie.,: how would produce a dimetric with inclination angles of 25_left - 25_right??