Decoding binary bitmasks (bitflags)

Scripting
1

Is there any function or an easy way to “reverse-engineer” a bitmask such as used in Rhino’s object types?

For example take the number 60 and decode it into 4+8+16+32?

Thanks, --Mitch

2

I guess I could do it like this:

def DecodeBinaryObjType(number):
    bin_str="{0:b}".format(number)
    bin_lst=[int(elem) for elem in bin_str]
    bin_lst.reverse()
    if bin_lst[0]: print "Points present"
    if bin_lst[1]: print "PointClouds present"
    if bin_lst[2]: print "Curves present"
    if bin_lst[3]: print "Surfaces present"
    if bin_lst[4]: print "Polysurfaces present"
    if bin_lst[5]: print "Meshes present"
    #etc.
    
DecodeBinaryObjType(60)
3

I slightly misunderstood what you were going for. It can be done neatly using bitmasks and boolean operators, but I thought you were asking for a RhinoScript solution.

Either way, here’s one way to do it in VB:

bitmaks.png729×742 36.5 KB

bitmask.gh (2.9 KB)

4

OK, thanks anyway for answering David! --Mitch