Int to String without decimal points?

Hey guys,

I’ve made a function to get the dimensions of my bounding box and i’m putting them into a sentence as a string by using str(varx)+srt(vary) etc.

I have even rounded the Integers by using Round() but when i turn them into strings, everything comes up with 1 decimal precision that’s always 0. (for example 125.0 x 450.0 x 1200.0)

how to get rid of that decimal?


You’ll need to post some code. Casting an integer to a string using str(myInt) does not add decimals.

Since you asked about splitting a string that’s how you do it

If you have any string, and you want to separate it on a specific char, you can use
So if you have a string 102.1 that you get from usertext, you can use Split which is rather faster than converting the string to a float, and then removing any decimal numbers.

splittedString[0] will be 102

That being said, since you’re starting off with a float, you can simply round the values, without splitting any strings

# Round your integers
varx = round(var1)
vary = round(var2)
varz = round(var3)

# Convert the rounded integers to strings with no decimal places
var_string = "{} x {} x {}".format(int(varx), int(vary), int(varz))

# Print the resulting string you will notice It's rounded

This is my code now.

def BoundingBox():
obj = rs.GetObject()
bb = rs.BoundingBox(obj, in_world_coords=True)

XL = bb[1].DistanceTo(bb[0])
YL = bb[3].DistanceTo(bb[0])
ZL = bb[4].DistanceTo(bb[0])

x = round(XL, 0)
y = round(YL, 0)
z = round(ZL, 0)

dims = str(x)+" x "+str(y)+" x "+str(z)+" h."

return dims

i then define a

dimensions = BoundingBox()

and in another defintion later, i print dimensions

Try changing this line:

dims = str(x)+" x "+str(y)+" x "+str(z)+" h."


dims = "{} x {} x {} h.".format(int(x),int(y),int(z))

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Works perfect, thanks!!

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In Python 3:

round( number )


round( number, None )

return an integer, but

round( number, 0 )

returns a float.

In Python 2:


always returns a float.

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