Understanding positive shift paths

Grasshopper
1

I understand the concept of negative offset in shift paths.

But I don’t understand how does positive offset works in this case. Can anyone please explain?

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SHIFT PATH QUESTIONS.gh (16.3 KB)

2

You can use the Param Viewer to see what the offset does to your trees:

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3

The concept is very simple. With negative numbers, Shift Paths works exactly like Trim Tree, eliminating a certain number of digits from the back of the branch addresses in a tree.

With positive numbers, it eliminates a certain number of digits from the front of the branch addresses in a tree.

Formerly disparate branches of the tree become merged if by trimming from the back or the front they form a common branch address.

4

Shift positive trims the tree paths starting from left and going to right.

In your example you have {0;0;0;A} on each list because:

  1. first zero is from the initial curve component
  2. second zero is beacuse you graft the curve component, putting each curve in a separate list (but the component had already just one item so nothing changes)
  3. third zero is after array component, putting each array in a separate list, one for each starting input (but you have only one, so again nothing changes)

zeros from points 2 and 3 (and maybe even 1) are not necessary in this particular case, so you can delete them the way you prefer

5

Got it. Thanks! This makes sense.

6

Thanks @Fabio_Franchetti , thanks @martinsiegrist :+1: