Simulate distance of 90 feet

I am creating a drawing of a public sculpture to be positioned 90 feet from the street. How do I see what that really looks like in a front view (elevation, not plan)? I know my 16’ high piece will look tiny from that distance, and a simulation will prove it to myself and others.

Kyle suggested that maybe Steve or an architect might have a way.

Can you help?
Thank you, Bill

Hi @William_Freer1

When you say front view you mean looking at your sculpture frontally? Because front view in Rhino is an orthogonal view and a construct which doesn’t exist in reality.

Make sure you have your four viewports open, top, front, right and perspective. Then with perspective view active hit the f6 key and bring up your camera. In top view move your camera back 90 feet. Notice how it updates in the perspective view. You can set your target and lens length in properties as well and both the size of your viewport and lens settings will have an effect on how much or how big your sculpture will appear.

You could also draw a line 90 feet long in top view, set one end to where you sculpture is (the target point) then in right view or front move the line up to your eye height which is roughly 4’9" average. Using snap to point snap your target to the sculpture end point of the line and the camera body to the other end of the line which would be viewer station point.
RM

Thank you, this is very helpful!