Python problem with fRange floating values

Grasshopper
1

Why does a 2.3333 appears? It should end at 2.0.

The goal is to set a size of x and y; and that within the size a resolution can be set wherein the size does not change, only the amount of points within the size as like a resolution.

It comes down to avoid the 2.3333, somehow it is overruled in my script.

python problem with fRange 01.gh (7.3 KB)

python%20problem%20with%20fRange%2001
python%20problem%20with%20fRange%20011163×859 70.2 KB

2

python problem with fRange 02.gh (5.9 KB)

import rhinoscriptsyntax as rs

def fRange(start, end, step):
    list = []
    list.append(start)
    temp = list[0]
    while (temp <= end):
        temp += (end/step)
        list.append(temp)
    list.pop(-1)
    return list


a = fRange(x, y, z)
3

frange() is a rhinoscript specific function. you can call it by using rs.frange(start, end, step). it is for numbers of the type “float”, hence the f in frange.
is this they type of thing you are after?
frange

import rhinoscriptsyntax as rs

def myFrange(x, y, z):
	vals = []
	for i in rs.frange(x, y, z):
		vals.append(i)
	if u:
		vals.append(y)
	else:
		pass
	return vals

a = myFrange(x, y, z)
1 Like
4

Chris Hanley is correct，But you can also try your method，I made some minor changes.like this

QQ%E6%88%AA%E5%9B%BE20180818235316
QQ截图20180818235316.jpg1219×403 48.9 KB

Code：
import rhinoscriptsyntax as rs

def fRange(start, end, step):
    list = []
    list.append(start)
    temp = start
    while (temp <= end):
        temp += step
        if(temp<=end):
            list.append(temp)
        else:
            list.append(end)
    return list


a = fRange(x, y, z)
1 Like
5

This is my interpretation of what you are trying to achieve. This gives the start value as x, the end value as y and the total number of steps (including the start and end) equal to z.

import rhinoscriptsyntax as rs

def fRange(start, end, step):
list = []
temp = start
qty = int(step-1)
list.append(start)
for i in range(0,qty):
temp += ((end-start)/(step-1))
list.append(temp)
return list

a = fRange(x, y, z)

1 Like