Hello!

Given a curve array, I’d like to get the tangents of each point on the curve.

ArrCurve outputs a ‘Transform’ - how would I convert this to a plane? Beause then I’d be able to get the point’s local coords with a ‘Deconstruct Plane’, including the tangents.

Thanks!

Best regards

Eugen

Found this solution: instead of using ‘Curve Array’,

‘Range’ can be used to create a list of length values along the curve, then ‘Evaluate Length’ to get the points on curve, which outputs the tangent, too.

Thanks anyway!